Find the period of the function.
y= 3 sin x/8

option b

16π

Step-by-step explanation:

Given in the question an equation,

y = 3sin(x/8)

We know that, the period of y = asin(bx) is given by

Period =

here,

a = 3

b = 1/8

so,

Period =  2π / (1/8)

           = 8(2π)

           = 16π

The period of the function is 16π .

answer: f true

step-by-step explanation:

the equivalent expression are always the hardest ones but you look at the gcf also

step-by-step explanation: