Two catalysts in a batch chemical process, are being compared for their effect on the output of the process reaction. a sample of 12 batches was prepared using catalyst 1, and a sample of 10 batches was prepared using catalyst 2. the 12 batches for which catalyst 1 was used in the reaction gave an average yield of 85 with a sample standard deviation of 4, and the 10 batches for which catalyst 2 was used gave an average yield of 81 and a sample standard deviation of 5. find a 90% confidence interval for the difference between the population means, assuming that the populations are approximately normally distributed with equal variances.

2.083 < µ1 - µ2 < 5.917  

Step-by-step explanation:

We will need to construct a 90% confidence interval for the difference of 2 means where the populations are normally distributed, and their variances are equal.

The calculations of the sample means and standard deviations are done for us.

Sample 1: Catalyst 1

n = 12, x = 85, s = 4

Sample 2:  Catalyst 2

n = 10, x = 81, s = 5

See attached photo for the construction of the confidence interval...

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.

false

step-by-step explanation: