Find a polynomial with degree 3; zeros -3,3,5

Step-by-step explanation:

f(x)= ax^3+bx^2+cx+d

f(-3)=-3a^3-3b^2-3c+d=0

f(3)=3a^3+3b^2+3c+d=0

f(5)=5a^3+5b^2+5c+d=0

f(0)=0a^3+0b^2+0c+d=2 <= any number you want your extremum at

=> d=2

f(-3)=-3a^3-3b^2-3c+=-2

f(3)=3a^3+3b^2+3c+=-2

f(5)=5a^3+5b^2+5c+=-2

solve for all variables ( Gauß )

a = 0.0266

b= -0.08

c= -0.66

As Solution

0.0266x^3-0.08x^2-0.66x+2 approximately

true !

step-by-step explanation:

i think it might be a but you might want a second opinion