What is the solution to the following system of equations?

The correct answer is first option (-5, 5)

Step-by-step explanation:

It is given that,

3x - 4y = -35 and 3x + 4y = 5

To find the solution

Let, 3x - 4y = -35   (1)

      3x + 4y = 5    (2)

Eq(1) + (2) ⇒

6x = -35 + 5  = -30

x = -30/6 = -5

ex(1) ⇒  3x - 4y = -35  

3 *-5  - 4y = -35

-15 - 4y = -35

4y = -15 + 35 = 20

y = 20/4 = 5

Therefore x = -5 and y = 5

The correct answer is first option (-5, 5)

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )

step-by-step explanation: