What is the area of a triangle with side that are 10 10 and 16

16√231 units²

Step-by-step explanation:

Because the triangle is isosceles, we can easily find the height. Splitting the triangle in half gives us a right triangle whose hypotenuse is 10 units, and one of the legs is 5 units.

We can use the Pythagorean Theorem: x² + 5² = 16² -> x² = 231 -> x = √231 (can not be simplified)

Now that we know the height, we can solve for the area. The base is 16, and the height is √231.

That gives us 16*√231 = 16√231 units².

(Heron's formula can be used, but in this situation, doing this takes less time)

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: