What is the smallest number of chickens that can walk in this formation: two chickens in front of a chicken, two chickens behind a chicken, and a chicken between two chickens?

3

Step-by-step explanation:

Suppose '@' represent a chicken

Step 1

Two chickens in front of a chicken

@

@

@

Step 2

Two chickens behind a chicken

@

@

@

Step 3

A chicken between two chickens

@

@

@

The smallest number of chickens that can walk in the given formation is 3.

Explanation:

Let us assume that the chickens are walking in a line,

Chicken 1--Chicken 2--Chicken 3

Given,

Situation 1: 2 chickens in front of 1 chicken  

That is 2 in front of 1 = 2+1=3 chicken

Situation 2: 2 chickens behind 1 chicken

That is 2 behind 1 = 2+1=3 chicken

Situation 3: 1 chicken between 2 chicken

1+1+1=3 chicken

From the 3 situations, we can conclude that the minimum number of chickens can possibly be 3.

answer:

it is general formula that is used to write value to its excet position

a11 a12 a13

a21 a22 a23

it is the example of order 2 by 3 matrix in this

a11 means value occur in 1 st row 1st column

a12 means value occurs in 1st row 2nd column

a13 means value occur in 1st row and 3rd column

a21 means value occurs in 2nd row and 1st column

a22 means value occurs in 2nd row and in 2nd column

a23 means value occurs in 2nd row and in 3rd column

answer: bearing in mind that a rectangle has a perimeter of length + length + width + width.

step-by-step explanation:

p = perimeter

l = length

x=width

p = 2l + 2x

p = 2(l+x)     < ==== perimeter of the base of the box.