Let k represent some unknown positive non-integer less than 1. where is each of the following located on a number line: -k, k-+2, k-3, √k, k² ?

k-3, k-2, -k, k^2, sqrt(k), k+2

Step-by-step explanation:

k issome unknown positive non-integrer less than one. It means that k belongs to the interval (0,1).

The minimum value that k can take is one close to 0. If we take k=0.1, we have:

0.1-3 = -2.9

0.1-2 = -1.9

-k = -0.1

For that reason, we know that k-3 < k-2 < -k. Those terms are located on the negative side of the number line.

Let's check the possitive side:

Given that k is a non-integer number less than 1, any number raised to the power of 2 is going to be less than the actual number. For that reason we locate k^2 next to zero.

Given that k is a non-integer number less than 1, the square rooth of any number is going to be greater than the actual number, but never greater than 1.. For that reason sqrt(k) > k^2.

Last but not least, k+2 is the greatest number of all. Because in all cases, the less value it can take is 2.

option a.

step-by-step explanation:

if you look closely at the graph, we can notice that the function is not defined at two different points.

if you look at functions b and c, you will notice that both functions are not defined at just one point. the function b is not defined at x= -5/2 and function c is not defined at x=-5. both options are discarded, given that our function should not be defined at two fiferent points.

now, if you look closely at the graph you will notice that the function sketched is not defined at x=5 and x=-2.

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: