The manager of the cheesecake factory in boston reports that on six randomly selected weekdays, the number of customers served was 120, 130, 100, 205, 185, and 220. she believes that the number of customers served on weekdays follows a normal distribution. construct the 90% confidence interval for the average number of customers served on weekdays. (you may find it useful to reference the t table. round intermediate calculations to at least 4 decimal places. round "sample mean" and "sample standard deviation" to 2 decimal places and "t" value to 3 decimal places and final answers to 2 decimal places.)

143.31 < µ < 176.69

Step-by-step explanation:

The manager wants a 90% confidence interval based on the data.  We are given 6 weekdays of data.   We have to do 3 things:

1.  Calculate the mean number of customers

2.  Calculate the standard deviation of the number of customers

3.  Construct the confidence interval

*For #1 and #2, see attached photo 1 for the calculations...

The sample mean is: 160

The sample standard deviation is: 20.29

The t-value we need is found using the t-distribution chart, with 5 degrees of freedom.  Our t-value is:  2.015

*See attached photo 2 for construction of the confidence interval

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r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option