Find the difference. (4x 2 - 6x + 8) - (3x 2 - 6x + 2)
x^2 + 6
7x^2 - 12x - 6
x^2 + 12x + 6
x^2 - 12x - 6

A. x^2 + 6

Step-by-step explanation:

(4x^2 - 6x + 8) - (3x^2 - 6x + 2) =

The first set of parentheses is unnecessary, so just remove it.

= 4x^2 - 6x + 8 - (3x^2 - 6x + 2)

To remove the second set of parentheses, change the sign of each term inside.

= 4x^2 - 6x + 8 - 3x^2 + 6x - 2

Now combine like terms.

= x^2 + 6

For this case we must find the difference of the following polynomials:

Taking into account that:

We have:

in problems involving proportions, we can use cross products to test whether two ratios are equal and form a proportion. to find the cross products of a proportion, we multiply the outer terms, called the extremes, and the middle terms, called the means.

hope it

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

eventually after a few more steps, your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x