What is the smallest number of chickens that can walk in this formation: two chickens in front of a chicken; two chickens behind a chicken, and a chicken between two chickens?

smallest number of chickens= 3

Step-by-step explanation:

In this question the given formation is:

two chickens in front of a chicken

the total number of chickens are 3

two chickens behind a chicken

the total number of chickens are 3

a chicken between two chickens

the total number of chickens are 3

So, the smallest number of chicken that can be required to make this formation will be 3.

So, if we consider that the chickens are walking in a straight line, two (2nd and 3rd) chickens will be behind the 1st chicken, two chickens( 1st and 2nd) will be in front of the last (3rd) chicken and one (2nd) chicken is in the middle of two (between 1st and 3rd) chicken.

the answer is:

the answer is:

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!