Solve the system of equations y = 2x - 4 y = x^2 - 4 a. (-3,5) and (3,5) b. (0,-4) and (2,0) c. (-1,-6) and (3,2) d. (0,4) and (2,1)

The answer is: B. (0,-4) and (2,0)

We can solve the system of equations using the substitution method, meaning that we must substitute one equation into the other equation, resulting in a principal equation.

So,

We are given two equations:

and,

So, making the equation equals, we have that:

Finding where the function tends to 0 (roots), we have:

Then, substituting each value of "x" in the first equation,  we will find the correct options:

Substituting "x" equal to 0 into the first equation, we have:

So, the point will be (0,-4)

Substituting "x" equal to 2 into the first equation, we have:

So, the point will be (2,0)

Therefore, the correct option is B. (0,-4) and (2,0)

Have a nice day!

B. (0,-4) and (2,0)

Step-by-step explanation:

The given system of equations is:

Equate both equations and solve for x.

Factor;

When x=0, y=2(0)-4=-4

Hence (0,-4) is one solution

When x=2, y=2(2)-4=0

Hence (2,0) is another solution

The correct choice is B.

v = 1/3 a^2h

step-by-step explanation:

the volume is 1/3 a^2h.