Super easy
at a game show, there are 6 people (including you and your friend) in the front row. the host randomly chooses 3 people from the front row to be contestants. the order which they are chosen does not matter. how many ways can you and your friend both be chosen?

20

Premutation: Order matters.

Combination: order doesn't matter.

n=6

r=3

Hope this helps!!!

It's B. The factorial of 6 is over 120 and the chances of BOTH friends "winning" is already low enough. Thus, 20, 30, and 120 make no logical sense.

Step-by-step explanation:

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)