The graph of f(x)=9(x-6)/x^2-7x+6 has a vertical asymptote at x=? ?

x=1

Step-by-step explanation:

First we need to simplify and factorize the denominator as shown below:

Following points must be kept in mind:

For x=6, both numerator and denominator are zero so we have a hole here. At x=1, only the denominator is zero, so we have a vertical asymptote here.

Thus the vertical asymptote of f(x) is at x=1

Step-by-step explanation:

For the function , you need to factor the denominator.

Find two number that when you add them you get -7 and when you multiply them you get 6. These numbers are -6 and -1.

Then:

Simplify:

Observe that the denominator is equal to zero in .

Therefore, when x approaches 1, f(x) tends to infinite.

Then the vertical asymptote s:

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ruth is 6 years old

step-by-step explanation:

6 + 24 = 30,   so 6/30 = .2  

if you do 1/5 it also equals .2, so that is the answer.