Apark in a subdivision has a triangular shape.2 adjacent sides of the park or 533 feet in 525 feet the angle between the sides is 53°. find the area of the park to the nearest square foot.
so much in : ))

The area of the park ≅ 111739 feet² ⇒ to the nearest square foot

Step-by-step explanation:

* Lets consider the subdivision is a triangle

- You can find the area of the triangle by :

# Case (1)

Area the triangle = 1/2 × the length of the base × the length of the height

* Were the base is one of the three side and the height is the perpendicular from the vertex opposite to this side to this side

# Case (2)

Area the triangle = 1/2 × side1 × side2 × sin the including angle between these two sides

* In the problem

∵ Side1 = 533 feet

∵ Side2 = 525 feet

∵ The measure of the angle between them = 53°

* We will use the second case to find the area of the park

∴ The area of the park = 1/2 × 533 × 525 × sin(53) ≅ 111739 feet²

the rocket cannot penetrate the ground, in a contextual sense, therefore the roots of this equation should be the domain of this function. i'll let you find the roots of this quadratic equation (hint: use the quadratic formula:  

1- c

2-a

step-by-step explanation:

mark brainliest!

step-by-step explanation: