Which equation could represent the graph shown below

f(x) = √(x+1) -2

Step-by-step explanation:

Since you're working with transformed functions, you know that replacing x with x-a in f(x) will translate the graph "a" units to the right. You also know that adding "b" units to the function value will translate the graph "b" units upward.

Here, the graph of f(x) = √x has been translated 1 unit to the left (a=-1) and 2 units down (b=-2). So, the transformed function is ...

f(x) = √(x-(-1)) + (-2)

f(x) = √(x+1) -2 . . . . . . simplify

playboycarti! *

she tryna be crate.

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: