Bearings are tricky and i though i had this

241°

Step-by-step explanation:

You are given the triangle internal angle (N) at Naples = 46°, and the side opposite a = 765 km. You are given the side b = 515 km, and asked to find an angle related to the internal angle opposite (C).

By the law of sines, the internal angle (C) at Canton is ...

sin(C)/b = sin(N)/a

C = arcsin((b/a)sin(N)) = arcsin(515/765·sin(46°)) ≈ 28.964°

The bearing from Elgin to Canton will be 270° less this angle, so is about 241°.

Comment on your answer

Apparently, you added 29° to 270°, rather than subtracting. Since the direction from Elgin to Canton is south of west, the bearing angle must be between 180° and 270°. Note that a line west from Elgin will be parallel to the line east from Canton, so you can take advantage of alternate interior angles being congruent where the Elgin-Canton line crosses those parallel east-west lines.

c.   x=2.4cm

step-by-step explanation:

similar triangles are triangles which have the same shape but not the same size. this means their angle measures are equal but their side lengths are not instead they are proportional. to solve, we will set up a proportion and solve.

a proportion is two equal ratios set equal to each other. we form the ratios by finding corresponding sides (sides which match to each other on both triangles by their position). out ratios will be one side of the small triangle over the corresponding side on the big triangle as shown below:

.

to solve the proportion, we'll cross multiply by multiplying numerator with denominator across the equal sign.

1. minimum

2. 6400

3. eight

hope this !