10 points

find an equation in slope-intercept form of the line that has slope –2 and passes through point a ( 1,9 )

a. y= -2x-11
b. y= 11x+2
c. y= -2x+11
d. y= 2x+ll

select the best answer from the choices provided

a
b
c
d

C. y= -2x+11

Step-by-step explanation:

We can use point slope form for the equation of a line

y-y1 = m(x-x1)

y-9 = -2 (x-1)

Distribute

y-9 = -2x +2

Add 9 to each side

y-9+9 = -2x+2+9

y = -2x +11

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

this is not a question