Aball is thrown vertically in the air with a velocity of 95ft/s. use the projectile formula h=−16t2+v0t to determine at what time(s), in seconds, the ball is at a height of 120ft. round your answer(s) to the nearest tenth of a second.

Step-by-step explanation:

If the equation represents the position of the ball as a function of time then, to find in which second the ball reaches 120 feet must substitute in the equation of the height and solve for t.

If the initial velocity is 95 feet/s then

Then:

Use the quadratic formula

Where, for this problem:

So

This result means that the ball reaches 120 feet for the first time at 1.8 seconds, then begins to descend and on its descent again reaches 120 feet at t = 4.1 seconds.

the answer is b.

step-by-step explanation:

identity property is where 0+whatever number=whatever number. basically 0+ a number.