What is the best approximation of the projection of (5, -1) onto (2, 6)

a. 0.10(5, -1)
b. 0.10(2, 6)
c. 0.15(2,6)
d.0.15(5. -1)

Answer with explanation:

Suppose we represent ordered pairs in terms of vectors.

Ordered pair of points , (5,-1) in terms of vectors is represented by = 5 i - j

Ordered pair of points , (2,6) in terms of vectors is represented by =2 i + 6 j

Projection of Vector A on Vector B

= 0.6324 (2,6)        

B. 0.10(2, 6)

Step-by-step explanation:

A careful graph of the vectors can help you answer this question. The end point of the projection of (5, -1) onto (2, 6) is (0.2, 0.6) = 0.10(2, 6).

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2