You are standing 45 meters from the base of the empire state building. you estimate that the angle of elevation to the top of the 86th floor(the observatory) is 82°. if the total height of the building is another 123 meters above the 86th floor, what is the total height of the building?
a) [45tan(82°) + 123] meters
b) [123tan(82°) + 45] meters
c) [45cos(82°) + 123] meters
d) [123cos(82°) + 45] meters

[45tan(82°)+123] meters

A is correct

Step-by-step explanation:

You are standing 45 meters from the base of the Empire State Building.

You estimate that the angle of elevation to the top of the 86th floor(the observatory) is 82°.

If the total height of the building is another 123 meters above the 86th floor.

OB = 45 m , ∠O= 82°

In Δ OBA, ∠B = 90°

Top of the building, T at 123 m from A

Total height of building = BA + AT

Hence, The height of building from ground is [45tan82°+123] meters

24/56=hx^7

step-by-step explanation:

2x^2+5x+17

your welcome. : )