Two clocks are circular. clock a has twice the area clock b. how many times greater is the radius of clock a than the clock b radius?

The radius of the circle A is times greater than the radius of circle B

Step-by-step explanation:

step 1

Find the scale factor

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

z-----> the scale factor

x----> the area of the clock A

y----> the area of the clock B

-----> equation A

we have

-----> equation B

substitute equation B in equation A

square root both sides

step 2

Find how many times greater is the radius of Clock A than the Clock B radius

we know that

If two figures are similar, then the ratio of its corresponding sides is equal to the scale factor

Let

z-----> the scale factor

x----> the radius of the clock A

y----> the radius of the clock B

we have

substitute

therefore

The radius of the circle A is times greater than the radius of circle B

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116