Y’all somebody me with

find the perimeter and area of the regular polygon .

Area = 166.28 units²

Perimeter = 48 units.

Step-by-step explanation:

This polygon has 6 sides.

Angle of each triangle at the centre of the circle is 360÷ 6 = 60º.

Since both the other angles at each triangle is equal (isosceles triangle), they are (180 - 60) ÷ 2 = 60º

We found out that all three angles are the same, 60º. This is an equilateral triangle.

Area of polygon = 6 [ 1/2 (8) (8) sin 60º ] = 166.28 units²

Perimeter of the polygon = 6 x 8 = 48 units

i = 2 / - 5

step-by-step explanation:

evaluation of ( 2 - 4 ) ( p + q ) when p = 2 and q = 5 i, by putting values of p and q,                                                                    

the mistake in the pattern is that :

b. the decimal point was moved one too many place values each time

the correct pattern could be made by :

b. moving the decimal point to the right the same numbers of place values as the exponents