Use the translation (x, y)→(x+6, y-3):
1.what is the image of a(3,2)?
2.what is the preimage of c'(2,-7)?
3.what is the image of b(-4,1)?
4.what is the preimage of d'(-3,-2)?

1. Plug the coordinates into the translation given: A(3,2) -> A'(3+6, 2-3) => A'(9, -1)
2. To find the preimage, you do the opposite: C'(2, -7) -> C(2-6, -7+3) => C(-4, -4)
3. Do the same as #1: B'(-4+6, 1-3) => B'(2, -2)
4. Do the same as #2: D(-3-6, -2+3) => D(-9, 1)