The heights (in cm) and arm spans (in cm) of 31 students were measured. the association between x(height) and y(arm span) is shown in the scatterplot below. the equation of the line of best fit modeling this relationship is given.
y=4.5x + 0.977x

mike is 175cm tall and george is 170cm tall.
using the model, how many centimeters longer would we expect mike's arm span to be than george's?

27.385 cm longer would we expect Mike's arm span to be than George's.

Step-by-step explanation:

We have to find how many centimeters longer would we expect Mike's arm span to be than George's using the equation:

y= 4.5x + 0.977 x

where y= arm span

and x= height

Given:

Mike's height=x = 175 cm

so Mike's arm span= y= 4.5 x + 0.977 x

                                    = 4.5* (175) + 0.977* (175)

                                    = 787.5 + 170.975

                                    = 958.475 cm

George's height = x = 170 cm

so George's arm span= y= 4.5 x + 0.977 x

                                    = 4.5* (170) + 0.977* (170)

                                    = 765 + 166.09

                                    = 931.09 cm

Mike's arm span longer than George's = Mike's arm span - George's arm span

                                                                 = 958.475 - 931.09

                                                                 = 27.385 cm.

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

y -5 = (-1/4)(x + 8)

step-by-step explanation: