Find the y-intercept for the parabola defined by the equation y=x^2-x-12

The y-intercept is (0,-12).

Step-by-step explanation:

Given equation is .

Now question says to find the y-intercept of the given parabola .

We know that y-intercept means the y-value when x-value equals 0

so let's plug x=0 into given equation  then solve that for y.

Hence the y-intercept is (0,-12).

the first one is x^2+2x+2

the second one is x^2+4

the last one is x^2-4x+8