Four friends were born on consecutive years the sum of their ages is 62 what is the youngest friend

The age of youngest friend = 14 years

Step-by-step explanation:

It is given that, four friends were born on consecutive years the sum of their ages is 62

Let 'x' be the age of youngest friend

age of other friends are (x + 1), (x + 2) and (x + 3)

To find the age of youngest friend

From the given information we can write,

x +  (x + 1) + (x + 2) + (x + 3) = 62

4x + 6 = 62

4x = 62 - 6 = 56

x = 56/4 = 14

Therefore age of youngest friend = 14

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

point a is the center of the circle that passes through points e, f, and g and the center of the circle that passes through points x, y, and z.