Me plz asap

two clocks are circular. clock a has twice the area as clock b. how many times greater is the radius of clock a than the clock b radius

The radius of clock A is √2 greater than the radius of clock B

The radius of clock A is 1.41 greater than the radius of clock B

Step-by-step explanation:

* Lets talk about the similar circles

- All the circles are similar because all the circles have the same

 measure 360° and there is a ratio between their radii

- If the ratio between the radii of two circles is a/b, then the ratio

 between their circumferences is also a/b

- If the ratio between the radii of two circles is a/b, then the ratio

 between their areas is (a/b)²

* Now lets solve the question

- Clock A has area twice the area as clock B

∴ Area of circle A = 2 Area of circle B

- If the ratio between their radii is a/b

∵ Area of circle A /area of circle B = 2

∴ (a/b)² = 2 ⇒ take a square root for both sides

∴ a/b = √2

∴ The radius of clock A is √2 greater than the radius of clock B

segment bisector

step-by-step explanation:

line segment bisector. definition: a line, ray or segment which cuts another line segment into two equal parts. try this drag one of the orange dots at a or b and note the the line ab always divides the line pq into two equal parts.

mark brainliest!