You spin a spinner divided into 6 equal sections and then flip a coin. if the spinner lands on 8, what is the probability that the coin will land heads up?
a. 0
b.1/8
c.1/6
d.1/2

1/2(i think)

Step-by-step explanation:

since a coin has two sides

the denominator would be 2

since the coin has 1 chance of it landing on heads and 1 chance of it landing on 2

the probability the coin will land on heads is 1/2

hope this helps!

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)