An organization consists of 8,684 employees. they decided to conduct a survey about their new vacation policies. the organization surveyed 884 of their employees and found that 36% of those surveyed disliked the new vacation policies. assuming a 95% confidence level, which of the following statements holds true?

a. as the sample size is appropriately large, the margin of error is ±0.032.

b. as the sample size is too small, the margin of error is ±0.032.

c. as the sample size is appropriately large, the margin of error is ±0.0265.

d. as the sample size is too small, the margin of error cannot be trusted..

i think the answer is a. am i correct?

The correct option is A.

Step-by-step explanation:

An organization consists of 8,684 employees. The organization surveyed 884 of their employees and found that 36% of those surveyed disliked the new vacation policies. It means

The value of z-score for 95% confidence level is 1.96.

The formula for margin of error is

Where, z is z-score at given confidence level, p is sample proportion and n is number of samples.

The margin of error is ±0.032 and the sample size is appropriately large. Therefore, the correct option is A.

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

: )

~dasgupta/mathbook/append17dec2k8.pdf