Arectangular exercise has a perimeter of 36 week the length of the mat is twice the width it right and solve and equation to determine the length of the feet of the mat then find the area in square feet of the mat

Part a) The length of the rectangle is

Part b) The area of rectangle is

Step-by-step explanation:

step 1

Find the length

Let

L-----> the length of the rectangle

W---> the width of the rectangle

we know that

The perimeter of rectangle is

so

----> equation A

-----> equation B

substitute equation B in equation A

solve for W

Find the value of L

step 2

Find the area

The area of rectangle is equal to

substitute the values

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)