![\displaystyle \lim_{h\to 0} \frac{\sqrt[3]{x+h}-\sqrt[3]{x}}{h}](/tpl/images/0270/3197/6af82.png)
![\dfrac{\sqrt[3]{x+h}-\sqrt[3]{x}}{h} = \dfrac{\left(\sqrt[3]{x+h}-\sqrt[3]{x}\right)\left(\sqrt[3]{(x+h)^2}+\sqrt[3]{x(x+h)}+\sqrt[3]{x^2}\right)}{h\left(\sqrt[3]{(x+h)^2}+\sqrt[3]{x(x+h)}+\sqrt[3]{x^2}\right)}](/tpl/images/0270/3197/cb61c.png)
![\dfrac{x+h-x}{h\left(\sqrt[3]{(x+h)^2}+\sqrt[3]{x(x+h)}+\sqrt[3]{x^2}\right)} = \dfrac{h}{h\left(\sqrt[3]{(x+h)^2}+\sqrt[3]{x(x+h)}+\sqrt[3]{x^2}\right)} = \dfrac{1}{\sqrt[3]{(x+h)^2}+\sqrt[3]{x(x+h)}+\sqrt[3]{x^2}}](/tpl/images/0270/3197/0cdcc.png)
![\displaystyle \lim_{h\to 0}\dfrac{1}{\sqrt[3]{(x+h)^2}+\sqrt[3]{x(x+h)}+\sqrt[3]{x^2}} = \dfrac{1}{\sqrt[3]{(x+0)^2}+\sqrt[3]{x(x+0)}+\sqrt[3]{x^2}} = \dfrac{1}{3\sqrt{x^2}}](/tpl/images/0270/3197/c6b48.png)
Find the derivative of the cube
root of x using first principle....
Mathematics, 28.09.2019 06:10 OGrant18075
Find the derivative of the cube
root of x using first principle.
Answers: 1
Another question on Mathematics
Mathematics, 21.06.2019 16:20
What are the soultion(s) to the quadratic equation 40- x^2=0
Answers: 1
Mathematics, 21.06.2019 17:30
How do i make someone brainliest? (if you answer me, i might be able to make you brainliest! )
Answers: 1
Mathematics, 21.06.2019 19:00
Tabby sells clothing at a retail store, and she earns a commission of 6.25% on all items she sells. last week she sold a pair of jeans for $32.50, a skirt for $18.95, and 2 blouses for $14.95 each. what was tabby's total commission? a $4.15 b $5.08 c $81.35 d $348.60
Answers: 3
Mathematics, 21.06.2019 21:00
Bo is buying a board game that usually costs bb dollars. the game is on sale, and the price has been reduced by 18\%18%. what could you find the answer?
Answers: 1
You know the right answer?
Questions
Mathematics, 28.08.2019 22:30
Computers and Technology, 28.08.2019 22:30
Biology, 28.08.2019 22:30
Computers and Technology, 28.08.2019 22:30
History, 28.08.2019 22:30
Physics, 28.08.2019 22:30
History, 28.08.2019 22:30
Computers and Technology, 28.08.2019 22:30
Mathematics, 28.08.2019 22:30
Mathematics, 28.08.2019 22:30
