3x=2^x+1 determine the number of solutions to each equation. then place each equation in the box that corresponds to its number of solutions.

TWO solutions

Step-by-step explanation:

If I interpret the right half of your equation to be 2^x     +    1, and then graph these two functions y = 3x and y = 2^x + 1 on the same set of coordinate axes, the graphs cross (intersect) in two places in Quadrant I.

y = 3x is a straight line graph with slope 3 through the origin (0, 0).

y = 2^x + 1 is an exponential function with y-intercept (0, 2) and horizontal asymptote y = 1.

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step-by-step explanation:

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