Alex put £350 into a building society savings account, which pays 6% simple interest each year. he didn't pay in or take out any other money, and after three years he went to check how much interest he had been paid.
(a) calculate the amount of interest he should have been paid each year;
(b) determine how much money he had in the account at the end of the 3 years
can someone explain this to i really don't get percentages.

a.) first year $371 second year $393.26 third year $416.90

b.)$416.90

Step-by-step explanation:

a(t)=p(1+(r/n))^nt

p=starting amount-350

r=rate-.06

n=the amount of times during the year the interest is paid-1

t=the time

350(1+(.06/1))^x

a.) first year $371 second year $393.26 third year $416.90

b.)350(1+(.06/1))^3

$416.90

you save $70

discount would be 35% off

step-by-step explanation:

you ignore the remainder, therefore the answer is y = x+2

step-by-step explanation:

you have to divide the denominator by the numerator. you can use synthetic division or long division.

[-5] .     1 .     7 .     11

x + 2 + 1/x+5