Find the axis of symmetry and vertex for the following equations. y=-x^2-4x+1

hello :

the axis of symmetry  is the line wher an equation is : x =2

the vertex is : (  2 ; 5 )

Step-by-step explanation:

write this expression in the vertex form :

y=-x²-4x+1

y = - ((x² +4x +4) -4) +1

y = - (x -2)²+5

the axis of symmetry  is the line wher an equation is : x =2

the vertex is : (  2 ; 5 )

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right