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a spring has spring constant 0.3 m/newton. what force is necessary to stretch the spring by 1.5 meters?

5 Newton

Step-by-step explanation:

We know that the Hooke's law states that the force 'F' needed to stretch or compress a spring by some distance 'a' is proportional to that distance .

, where c is the spring constant.

Given: A spring has spring constant 0.3 m/newton.

The  force is necessary to stretch the spring by 1.5 meters is given by :-

Hence, the  force is necessary to stretch the spring by 1.5 meters = 5 Newton .

kk.bj.

step-by-step explanation:

.mnm.kn.kj

answer: - (a)

(b) 88 seats

step-by-step explanation:

given: in an auditorium, there are 22 seats in the first row and 28 seats in the second row.

thus first term=

second term=

the number of seats in a row continues to increase by 6 with each additional row.

⇒d= 6

a) given formula :

b)   let the number of seats (n) = 12

substitute n=12 in the explicit rule formed in (a)

∴there are 88 seats in 12 rows.