Aquadratic equation is shown below

16x^2-8x+1=0

part a: describe the solution(s) to the equation by just determining the radicand. show your work

part b: solve 4x^2-8x-45=0 using an appropriate method

see explanation

Step-by-step explanation:

A

Given

16x² - 8x + 1 = 0 ← in standard form

with a = 16, b = - 8 and c = 1

Consider the discriminant

Δ = b² - 4ac = (- 8)² - (4 × 16 × 1) = 64 - 64 = 0

This indicates that the equation has 1 real root

B

Using the quadratic formula

x = ( - (- 8) ± ) / (2 × 16)

  = ( 8 ± 0 ) / 32

Hence x = = ← 1 real root

1)is not similar since corresponding sides are not in the same ratio

2)are similar since corresponding sides are in the same ratio and corresponding angles are equal

hope it will

#faazmessi

since proposition states that a number is greater than 25, if is true then the number must actually be greater than 25.

this implies that all possible options, except 24, can be accepted