Find the value of x shown in the isosceles triangle shown below
40

x = sqrt(41)

Step-by-step explanation:

We have a right triangle with height 5 and a base that is 1/2 of 8 = 4

We can use Pythagorean theorem

a^2 + b^2 = c^2 to find the length of the hypotenuse

5^2 + 4^2 = x^2

25+16 = x^2

41 = x^2

Take the square root of each side

sqrt(41) = x

i dont know sorry

step-by-step explanation: