Suppose that there are two types of tickets to a show: advance and same-day. advance tickets cost $35 and same-day tickets cost $15. for one performance, there were 60
tickets sold in all, and the total amount paid for them was $1300. how many tickets of each type were sold?

For this case we have:

x: Variable representing the types of advance input

y: Variable representing the same-day entry types

We have according to the cost:

According to the number of tickets:

We have a system of two equations with two unknowns:

We multiply the second equation by -35:

We add:

Thus, 40 same-day tickets were sold.

20 advance tickets were sold

20 advance

40 same-day

c - they will have the same distribution

step-by-step explanation:

this is the only one that could make sense. : )

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~