![\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=3\\ h=4 \end{cases}\implies V=\cfrac{\pi (3)^2(4)}{3}\implies V=12\pi \implies V\approx 37.7](/tpl/images/0469/0290/3e6f8.png)
![\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=3 \end{cases}\implies V=\cfrac{4\pi (3)^3}{3}\implies V=36\pi \\\\\\ \stackrel{\textit{half of that for a semisphere}}{V=18\pi }\implies V\approx 56.55](/tpl/images/0469/0290/2d561.png)
(i've been trying to figure this out for 3 days and i really need )
1. you are opening a...
Mathematics, 24.01.2020 17:31 cdjeter12oxoait
(i've been trying to figure this out for 3 days and i really need )
1. you are opening a snow cone stand. your cups, which are shaped like a cone, are 4" tall and have a 6" diameter. how much room is there in the cone without a top on the snow cone? (filled to the brim only)
2. the top of your snow cone is a perfect semicircle. it goes all the way across the cone. how many cubic inches of ice in the top of the snow cone?
3. how many cubic inches of snow cone will you be serving?
4.you want to start selling 2 different sizes of cones. you want your new cone to be twice as big as your current cone (top included). you found a cone that has a 6" diameter and is 8" tall. how many cubic inches of snow cone will you have with the new cone?
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