Abox contains 3 blue marbles, 5 red marbles, and 4 white marbles. if one marble is drawn at random, find p(not red inot white). enter your answer in decimal form rounded to two decimal places.

p(a|b)= p(a and b)

p(b)

Step-by-step explanation:

p(b)=3/12 = 0.25

p(r)=5/12 = 0.42

p(w)=4/12 = 0.33

p(¬r) = 1-0.42 = 0.58

p(¬w)= 1-p(w) = 0.67

P(not red Inot white)= 0.58/0.67=0.87

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)