The formula for determining the frequency, f, of a note on a piano is f=440(2)^h/12 where h is the number of half-steps from the a above middle c on the keyboard. a note is six half-steps away from the a above middle c. the frequency of the a above middle c is 440 hz. how much greater is the frequency of the new note compared with the frequency of the a above middle c?
a)29.3%
b)41.4%
c)70.7%
d)182.3%

41.4%

Step-by-step explanation:

The formula for determining the frequency:  --A

where h is the number of half-steps from the A above middle C on the keyboard.

A note is six half-steps away from the A above middle C.

Now we are supposed to find How much greater is the frequency of the new note compared with the frequency of the A above middle C?

Now initially there is no half steps .

So, substitute h =0

Now we are given that A note is six half-steps away from the A above middle C

So, substitute h =6

Now To find change percentage

Formula:

Hence  the frequency of the new note is 41.4% greater with the frequency of the A above middle C.

idk

step-by-step explanation: