Triangle abc has points a(2, -1), b(3, 4), c(-7, 2), and is dilated by a factor of 5 to create the triangle a'b'c'. what are the coordinates of triangle a'b'c'?

Step-by-step explanation:

You know that the triangle ABC has these points:

A(2, -1), B(3, 4), C(-7, 2)

If the triangle ABC is dilated by a factor of 5 to create the triangle A'B'C', you can find the coordinates of this new triangle by multiplying by 5 the coordinates of the triangle ABC given.

Therefore, the coordinates of the triangle A'B'C' are:

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50

whats the question?

step-by-step explanation: