What is the length of each side of the larger square

The larger square is 6 cm on a side

Step-by-step explanation:

Let x = the side of square 1

Let y = side of square 2

A= s^2

Area of square 1 = x^2

Area of square 2 = y^2

The total area of both squares = x^2 +y^2 = 45

We know that y = 2x

Substituting in

x^2 + (2x)^2 = 45

x^2 +4x^2 = 45

5x^2 = 45

Divide each side by 5

5x^2/5 = 45/5

x^2 = 9

Take the square root of each side

sqrt(x^2) = sqrt(9)

x = 3

y = 2x = 2(3) = 6

The larger square is 6 cm on a side

let x and 400 - x be the two numbers.  

==> 0.80x + 0.85(400 - x) = 400 - 68 from the statement of the problem.  

< ==> 0.80x + 0.85(400 - x) = 400 - 68  

==> 340 - 0.05x = 332  

< ==> -0.05x = -8 ==> x = 160, the first number ==> 400 - x = 240, the second number.