At the beginning of year 1, bode invests $250 at an annual simple interest rate of 3%. he makes no deposits to or withdrawals from the account. which explicit formula can be used to find the account’s balance at the beginning of year 14? what is the balance?
a. a(n) = (250)(n – 1)(0.03); $97.50 b. a(n) = 250 + (n)(0.03 • 250); $355.00 c. a(n) = 250 + (n – 1)(0.03); $250.39 d. a(n) = 250 + (n – 1)(0.03 • 250); $347.50

D.A(n) = 250 + (n – 1)(0.03 • 250); $347.50

Step-by-step explanation:

we know that

The simple interest formula is equal to

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

in this problem we have

substitute in the formula above

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560

d. you cannot tell because there are no values shown.