10
what is the x-value of the
intersection for the lines?
2x +y=-4
- 3y = 2x + 12
record your answer and fill in
the bubbles on your answer
document.
be sure to use the correct place value,

0

Step-by-step explanation:

1) Multiply the first equation by -3:  -6x - 3y = 12

2) Substitute 2x + 12 for -3y in the above equation, obtaining:

-6x + 2x + 12 = 12

Then -4x = 0, and x = 0.  Letting x = 0 in the first equation, we get:

0 + y = -4, so y = -4.

The x-value at the intersection of the lines is zero (0).

That intersection is at (0, -4).

could you reply to this with the question so i can ?

step-by-step explanation:

here's what happens:

1) the graph of f   = x^2 is shifted 2 units to the right.

2) the resulting graph is reflected in the x-axis, so that the parabola now opens down.

3) this final result is transformed up by 5 units.