Let f(x)= cos(2x) +e^(-x). for what value of x on the interval (0,3) will f have the same instantaneous rate of change as the average rate of change of f over the interval?

is continuous on [0, 3] and differentiable on (0, 3), so the mean value theorem applies here. It says that there is some in the open interval (0, 3) such that

We have

so

answer: f = 32.2m

step-by-step explanation: that is the answer

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)