The library sponsors a chess club for members of all ages and skill levels. currently, the ages of the members are 7, 9, 10, 11, 13, 14, 15, 16, 18, 19, 20, 21, and 22. the librarian uses a histogram to track the number of members in different age groups. for this situation, which is the appropriate way to label the age intervals on the x-axis? a) 7−11; 11−14; 15−19; 20−22 b) 7−10; 11−14; 15−18; 19−22 c) 7−10; 10−15; 15−19; 19−22 d) 7−13; 15−19; 20−22

The appropriate way to label the age intervals on the x-axis is:  Option: B

               B)7−10; 11−14; 15−18; 19−22

            The rule for determining the number of intervals is:

Here we have 13 observations

and √(13)=3.6055≈4

Hence, we have a total of four intervals.

                 The width of each interval is calculated as:

                       i.e.   (22-7)/4=15/4=3.75≈4

We know that for classifying a class interval in a histogram the width of each of the interval must be equal.

A) 7−11; 11−14; 15−19; 20−22

In option: A--

the width of first interval is: 4

width of second interval is: 3

Width of third interval is: 4

Width of fourth interval is: 2

Hence, the width of each interval is not equal.

Hence, option: A is discarded.

C) 7−10; 10−15; 15−19; 19−22

In option: C--

the width of first interval is: 3

width of second interval is: 5

Width of third interval is: 4

Width of fourth interval is: 3

Hence, the width of each interval is not equal.

Hence, option: C is discarded.

D)  7−13; 15−19; 20−22

In option: D--

the width of first interval is: 6

width of second interval is: 4

Width of third interval is: 2

Hence, the width of each interval is not equal.

Hence, option: D is discarded.

B)  7−10; 11−14; 15−18; 19−22

There are a total of 4 intervals and also width of each interval is equal and equal to 4.

         Hence, option: B is the correct answer.

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