Need to find the zeros for this quadratic equation

see explanation

Step-by-step explanation:

Given

y = x² + 2x + 1

To find the zeros let y = 0, that is

x² + 2x + 1 = 0 ← x² + 2x + 1 is a perfect square

(x + 1)² = 0

x + 1 = 0 ( subtract 1 from both sides )

x = - 1 with multiplicity 2 ← zero

This indicates that the graph has a minimum turning point at (- 1, 0)

Note from your table

the value for x = - 1 should be y = 0 ( not - 2 )

1e+27

step-by-step explanation:

d) 48

step-by-step explanation:

16,32,48,64,80,96,112,128,144,160,176,192,208,224,240,256,272,288,304,320,336