What are the equations for the asymptotes of this hyperbola?

D

Step-by-step explanation:

The question is on asymptotes of a hyperbola

General equation for a hyperbola is; (x-h)² /a² - (y-k)²/b² =1

given  y²/36 - x²/121 =1

then h=0 and k=0 thus  Center of hyperbola= (0,0) at the origin.

b²=36,b⇒6   a²=121, a⇒11

Vertices of hyperbola v=( h+a, k) and (h-a, k) = (11,0) and (-11, 0)

Equation of asymptotes is given by;

y=k ± b/a (x-h) and we have found that a=11 and b=6

hence y=0 ± 6/11(x-0)

y=6/11 x and y= -6/11 x

Option D

and

Step-by-step explanation:

We know that the general equation of a hyperbola with transverse vertical axis has the form:

Where the point (h, k) are the coordinates of the center of the ellipse

2b is the length of the transverse horizontal axis

2a is the length of the conjugate axis

The asymptotes are lines to which the hyperbola graphic approaches but never touches.

The asymptotes have the following equation

Where

In this case the equation of the ellipse is:

Then

The asymptotes are:

see the attached image

answer: just subtact the units and then add the non negative : happy to

step-by-step explanation:

where r the answers

step-by-step explanation: