An airplane is flying at an altitude of 2.7 miles and is 8.3 miles from the runway. find the angle of depression that the airplane must make to land safely?

Step-by-step explanation:

Let

x-----> the angle of depression

we know that

The sine of angle x is equal to divide the altitude (opposite side to angle x) by the distance from the runway (hypotenuse)

18.02°

Step-by-step explanation:

Formula to find angle of depression is given as

tan y = opposite / adjacent

where y = angle of depression

Where opposite = height or altitude of a person or thing

adjacent = distance

In this question ,

opposite = altitude of the plane = 2.7 miles

adjacent = distance of the plane from the runaway = 8.3 miles

Angle of depression is calculated as

tan y = ( 2.7/8.3)

y = tan⁻¹ ( 2.7÷8.3)

y = 18.02°

Angle of depression that the plane must make to land safely = 18.02°

2/3

step-by-step explanation:

the slope of a line is equal to the rise/run. in this case the line rises 2 units for every +3 units it moves